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25x^2+0x-9=0
We add all the numbers together, and all the variables
25x^2+x-9=0
a = 25; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·25·(-9)
Δ = 901
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{901}}{2*25}=\frac{-1-\sqrt{901}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{901}}{2*25}=\frac{-1+\sqrt{901}}{50} $
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